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// This file test stack parsing capabilities of KDbg.
// Parsing function names can be quite tricky ;)
#include <iostream>
using namespace std;
struct S {
void operator>>(int)
{
cout << __PRETTY_FUNCTION__ << endl;
}
};
template<typename T>
struct templS {
void operator>(T)
{
cout << __PRETTY_FUNCTION__ << endl;
}
void operator<(T)
{
cout << __PRETTY_FUNCTION__ << endl;
}
};
namespace A {
namespace {
namespace B {
namespace {
namespace {
void g()
{
cout << __PRETTY_FUNCTION__ << endl;
}
} // namespace
void Banong() { g(); }
} // namespace
void g() { Banong(); }
} // namespace B
void Aanong() { B::g(); }
} // namespace
void g() { Aanong(); }
void operator<<(int, S)
{
cout << __PRETTY_FUNCTION__ << endl;
}
template<typename T>
void operator<(T, S)
{
cout << __PRETTY_FUNCTION__ << endl;
}
} // namespace A
void operator<<(struct S&, int)
{
cout << __PRETTY_FUNCTION__ << endl;
}
template<typename T, typename U>
void operator<<(T&, U)
{
cout << __PRETTY_FUNCTION__ << endl;
}
void operator<(struct S&, int)
{
cout << __PRETTY_FUNCTION__ << endl;
}
template<typename T, typename U>
void operator<(T&, U)
{
cout << __PRETTY_FUNCTION__ << endl;
}
void f(const char* s)
{
A::g();
cout << s << endl;
}
template<typename T>
void indirect(T f, const char* s)
{
f(s);
}
int main()
{
S s1, s2;
f("direct");
s1 << 1;
s1 << s2;
s1 < 1;
s1 < s2;
A::operator<<(1, s1);
A::operator<(1, s1);
// the next lines test a templated function that accepts
// as one of its parameters a templated function pointer
void (*op1)(S&, S*) = operator<<;
operator<<(op1, s2);
void (*op2)(S&, S*) = operator<;
operator<(op2, s2);
indirect(f, "indirect");
// pointer to member function
void (S::*pm1)(int) = &S::operator>>;
(s1.*pm1)(1);
void (templS<int>::*pm2)(int) = &templS<int>::operator>;
templS<int> tSi;
(tSi.*pm2)(1);
tSi.operator<(1);
}
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