1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
|
/*
* Copyright (c) 2001 Mikhail Kourinny (mkourinny@yahoo.com)
*
* This program is free software; you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation; either version 2 of the License, or
* (at your option) any later version.
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
* You should have received a copy of the GNU General Public License
* along with this program; if not, write to the Free Software
* Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA.
*/
#include "adviseFast.h"
#include <algorithm>
using namespace AdviseFast;
std::ostream &AdviseFast::operator <<(std::ostream &s, Fact const &f)
{
return s << f.pointSet << "= " << f.mines;
}
AdviseFast::FactSet::FactSet(BaseField *field) :
_field(field)
{
Fact globalFact; globalFact.mines = field->nbMines();
int i, j;
for(i=field->height()-1; i>=0; --i)
for(j=field->width()-1; j>=0; --j){
Coord p(j, i);
// #### hasMine implies isCovered (and the solver should not
// know if there is a mine :) [NH]
if ( field->isCovered(p) /*|| field->hasMine(p)*/ )
globalFact.pointSet.insert(p);
else {
Fact f;
this->retrieveFact(p, &f);
this->addFact(p, f);
}
}
this->addFact(Coord(-1,-1), globalFact);
}
void AdviseFast::FactSet::retrieveFact(
Coord which,
Fact *where)
{
where->mines = (_field->isCovered(which) ? -1
: (int)_field->nbMinesAround(which));
CoordList tmp = _field->coveredNeighbours(which);
for (CoordList::const_iterator it = tmp.begin(); it!=tmp.end(); ++it)
where->pointSet.insert(*it);
}
void AdviseFast::FactSet::addFact(
Coord const &point,
Fact const &fact)
{
if(this->count(point)) this->deleteFact(point);
Fact &f = ((*this)[point] = fact);
// Remove marked points
CoordSet marked;
set_intersection(
f.pointSet.begin(),
f.pointSet.end(),
_marked.begin(),
_marked.end(),
inserter(marked, marked.begin()));
CoordSet::iterator i;
for(i=marked.begin(); i!=marked.end(); ++i)
f.pointSet.erase(*i);
f.mines -= marked.size();
// Don't insert empty fact
if(f.pointSet.empty()) { this->erase(point); return;}
for(i=f.pointSet.begin(); i!=f.pointSet.end(); ++i)
_containingFacts[*i].insert(point);
}
void AdviseFast::FactSet::deleteFact(
Coord const &point)
{
if(!this->count(point)) return;
CoordSet::iterator i;
Fact &f = (*this)[point];
for(i=f.pointSet.begin(); i!=f.pointSet.end(); ++i){
_containingFacts[*i].erase(point);
if(_containingFacts[*i].empty())
_containingFacts.erase(*i);
}
this->erase(point);
}
bool AdviseFast::FactSet::reveal(
Coord point,
CoordSet *affectedFacts)
{
// Tolerate :)
if( !_field->isCovered(point) ) return true; // :)
CoordList tmp;
if(_field->doReveal(point, &tmp, 0) == false)
// Blew up :(
return false;
CoordSet autorevealed;
for (CoordList::const_iterator it = tmp.begin(); it!=tmp.end(); ++it)
autorevealed.insert(*it);
autorevealed.insert(point);
affectedFacts->insert(autorevealed.begin(), autorevealed.end());
CoordSet::const_iterator i;
for(i=autorevealed.begin(); i!=autorevealed.end(); ++i)
{
// I still think that each poing will belong to
// at least one fact, but don't want to waste time
// proving it :)
if(_containingFacts.count(*i)){
CoordSet const &affF = _containingFacts[*i];
affectedFacts->insert(
affF.begin(), affF.end());
for(CoordSet::const_iterator j=affF.begin();
j!=affF.end();
++j)
{
(*this)[*j].pointSet.erase(*i);
if((*this)[*j].pointSet.empty())
this->erase(*j);
}
_containingFacts.erase(*i);
}
Fact f; retrieveFact(*i, &f);
this->addFact(*i, f);
}
return true;
}
void AdviseFast::FactSet::mark(
Coord point,
CoordSet *affectedFacts)
{
if(_marked.count(point)) return;
_marked.insert(point);
// I still think that each poing will belong to
// at least one fact, but don't want to waste time
// proving it :)
if(_containingFacts.count(point)){
CoordSet const &affF = _containingFacts[point];
affectedFacts->insert(affF.begin(), affF.end());
for(CoordSet::const_iterator i=affF.begin(); i!=affF.end(); ++i){
(*this)[*i].pointSet.erase(point);
(*this)[*i].mines--;
if((*this)[*i].pointSet.empty())
this->erase(*i);
}
_containingFacts.erase(point);
}
_field->doMark(point);
}
CoordSet const *AdviseFast::FactSet::getContainingFacts(
Coord const &point) const
{
if(_containingFacts.count(point))
return &const_cast<std::map<Coord, CoordSet> &>(_containingFacts)
[point];
else return 0;
}
std::ostream &AdviseFast::operator <<(std::ostream &s, FactSet const &fs)
{
FactSet::const_iterator i;
for(i=fs.begin(); i!=fs.end(); ++i)
s << i->first << ": " << i->second << endl;
return s;
}
bool AdviseFast::adviseFast(
Coord *,
FactSet *,
RuleSet *)
{ return false;}
|
