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+From rabaca@nova.ov.ufrj.br Fri Oct 20 23:12:11 2000
+Return-Path: <rabaca@nova.ov.ufrj.br>
+Delivered-To: coolo@master.kde.org
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+ for coolo@kde.org; Fri, 20 Oct 2000 19:14:00 -0200
+From: Carlos Roberto Raba<E7>a <rabaca@nova.ov.ufrj.br>
+Reply-To: rabaca@nova.ov.ufrj.br
+Organization: Observatorio do Valongo - UFRJ
+To: Stephan Kulow <coolo@kde.org>
+Subject: Re: Moon tool
+Date: Fri, 20 Oct 2000 17:10:39 -0200
+X-Mailer: KMail [version 1.0.29]
+Content-Type: text/plain
+References: <00102016004500.08951@nova.ov.ufrj.br> <39F09247.5715C35D@kde.org>
+In-Reply-To: <39F09247.5715C35D@kde.org>
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+Message-Id: <00102019130700.09050@nova.ov.ufrj.br>
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+Status: O
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+
+Stephan,
+
+> In KDE2 I implemented free choice view angle, so I could also slide
+> it some degrees off to see it like I see it here :)
+
+It is nice to hear that! Unfortunately, I still use KDE 1.1.2.... By the way,
+when is the final release o 2.0?
+
+> But if you're an expert, I would like your advise on the correct
+> terms. Where on the earth you see the moon in the the default view
+> you can see on web pages etc.?
+
+As you know, the moon keeps always the same face turned to earth (the so called
+near side). This is a composition of its period of orbital motion and rotation:
+they are approximately the same. The moon's orbit is inclined with respect to
+the equator by (only) 5 degrees, and for our purposes, keeps the polar
+orientation in the sky unchanged. This means that the angle that you
+see the moon in the sky changes by a composition of two factors only: 1)
+latitude of the observer, and 2) time of the day that you look at the moon. If
+you look at the moon over many hours, the change of orientation in the sky is
+moon's orbital plane is close to the equator (as I said before) the discussion
+of orientation looses any meaning. At these positions, the passage by the
+meridian happens very close to the top of your head. So, I can be facing east
+and move my head up to see the moon, or I can be facing west and move my head
+up. Which rotation should I addopt? That is why I told you to use 0 or 180
+degrees. Otherwise, you would need to incorporate in your code many otherif he
+relations, including the latitude of the observer.he will see the first quarter
+moon as a C and the last quater moon as a D (see
+> The current kmoon uses the pictures of this site:l) when the moon is over
+> http://timbeauchamp.tripod.com/moon/, but a (german) colleague ofes over his
+> yours pointed out that the images are mirrored horizontally, son is reversed.
+> we corrected that (the larger craters appear on the left ontor. Since the
+> the moon I see in the sky, while they are right on the web).
+
+My colleague is correct. The east-west sides in the pictures are wrong, so you
+should flip them sideways. For an observer in the northern hemisthere this is
+all you need to do. For an observer in the southern hemisphere, you need to
+rotate this new set of images by 180 degrees. Keep in mind that in the sky if
+north is up east is to the left, if south is up east is to the right. You can
+easily see this if you lay down ;-/ on the floor with you head/legs pointing to
+the north/south line. Now, try to point your left arm to the geographic
+east while facing up.
+
+I hope this helps you. If you like more info, it will be a pleasure to
+help. Best wishes,
+
+Carlos